Problema Solution
In a basketball game, Team A defeated Team B with a score of 69. Team A won by scoring a combination of two-point baskets, three-point baskets, and one-point free throws. The number of two-point baskets was three more than the number of free throws. The number of free throws was three more than five times the number of three-point baskets. What combination of scoring accounted for the Team A's 69 points?
Answer provided by our tutors
let
x = the number of two-point baskets
y = the number of tree-point baskets
z = the number of one-point throws
Team A defeated Team B with a score of 69:
2x + 3y + z = 69
The number of two-point baskets was three more than the number of free throws:
x = 3 + z
The number of free throws was three more than five times the number of three-point baskets:
z = 3 + 5y
by solving the system of equations:
2x + 3y + z = 69
x = 3 + z
z = 3 + 5y
we find:
x = 21 two-point baskets
y = 3 tree-point baskets
z = 18 one-point free throws
click here to see the step by step solution of the system of equations:
Team A scored 21 two-point baskets, 3 tree-point baskets and 18 one-point free throws.