Problema Solution
Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 1 2 hours one bus reached town B, while the other bus was away from town B at a distance equal 1 6 of the distance between A and B. Find the speed of the buses and the distance between A and B.
Answer provided by our tutors
let
v + 10 = the speed of the traveling from A to B, v>0
v = the speed of the traveling from B to A
t = 3 1/2 hr = 3.5 hr the time of the travel
d = the distance between A and B, d>0
(1/6)d = the distance that the bus traveling from B to A has made
since speed = distance/time we have
v + 10 = d/3.5
v = ((1/6)d)/3.5
by solving the above system of equations we find:
d = 42 mi
v = 2 mph
click here to see the step by step solution of the system of equations:
v + 10 = 2 + 12 = 12 mph
the speed of the buses are: 12 mph and 2 mph.
the distance between A and B is 42 miles.