Problema Solution
Linda drove to Sacramento, which is 90 miles away. If she had been able to average 30 miles per hour faster, she could have saved an half hour. How fast was she going?
Answer provided by our tutors
let
v = the Linda's average speed, v>0
v + 30 = the average speed 30 mph faster
d = 90 mi the distance passed
since speed = distance/time follows time = distance/speed
d/v = d/(v + 30) + 1/2
90/v = 90/(v + 30) + 1/2
by solving we find:
v = 60 mph
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Linda was going with 60 mph.