Problema Solution
two men can do a piece of work in 15 days. they worked together for 6 days, one leaves and the other finishes the work in 12 days. how many days does it take for each alone?
Answer provided by our tutors
let
x = the number of days the first worker needs to finish the job alone
1/x job per hour the rate of the first worker
y = the number of days the first worker needs to finish the job alone
1/y job per hour the rate of the second worker
1/15 job per hour the together rate
1/x + 1/y = 1/15
they worked together for 6 days, one leaves and the other finishes the work in 12 days:
6/15 + 12/x = 1
by solving for x we find:
x = 20 days
click here to see the step by step solution of the equation:
plug x = 20 into 1/x + 1/y = 1/15
1/20 + 1/y = 1/15
by solving we find:
y = 60 days
click here to see the step by step solution of the equation:
the first worker can finish the work alone in 20 days.
the second worker (the one that leaves) can finish the work alone in 60 days.