Problema Solution
Two cars leave at the same location. Car1 leaves at noon traveling at 40mph. Car2 leaves at one traveling 64 mph. How long does each car travel before they are side by side?
Answer provided by our tutors
let
v1 = 40 mph the speed of car 1
v2 = 64 mph the speed of car 2
t = the time of the travel of car 1
t - 1 = the time of the travel of car 2
since speed = distance/time follows distance = speed*time
v1*t = v2(t - 1)
40t = 64(t - 1)
by solving we find:
t = 8/3 hr
t = 2 hr 2*60/3 min
t = 2 hr 40 min
click here to see the step by step solution of the equation:
car 1 travels 2 hours and 4 min and car 2 travels 1 hr 40 min.