Problema Solution
Suppose a subset of 8 different days of the year is selected at
random. What is the probability that each day is from a different month? (For
simplicity, assume a year has 12 months and 30 days in each.)
Answer provided by our tutors
C(n, k) = n!/(k!(n - k)!)
(C(12, 8)*C(30,1)^8)/C(360, 8) = ((12!/(8!(12 - 8)!))*30^8)/(360!/(8!(360 - 8)!) = 5*6*7*8*9*10*11*12*(30^8)/(353*354*355*356*357*358*359*360) = 0.0502 or 5.02%