Problema Solution

One angle of a triangle has a measure of 47 degrees. Of the

other two angles, one of them is 3 degrees smaller than three

times the other angle. Find the measures of the two

remaining angles.

Answer provided by our tutors

let A, B and C represent the angles of the triangle


A = 47 degrees


A + B + C = 180


47 + B + C = 180


of the other two angles, one of them is 3 degrees smaller than three times the other angle:


B = 3C - 3


by solving the system of equations:


47 + B + C = 180


B = 3C - 3


we find:


B = 99 degrees


C = 34 degrees


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the measures of the two remaining angles are: 99 degrees and 34 degrees.