Problema Solution

four brothers play in a cricket team. In their last match Jim scored 15 more runs than Norman, Dennis scored 5 times as many as Norman and sixteen more than Pete. In total they scored 107 runs. How many did each brother score?

Answer provided by our tutors

let


j = the number of runs Jim scored


n = the number of runs Norman scored


d = the number of runs Dennis scored


p = the number of runs Pete scored


In their last match Jim scored 15 more runs than Norman,


j = 15 + n


Dennis scored 5 times as many as Norman


d = 5n


and sixteen more than Pete


d = 16 + p


p = d - 16


p = 5n - 16 (since d = 5n)


In total they scored 107 runs:


j +n + d + p = 107


plug j = 15 + n, d = 5n and p = 5n - 16 into the last equation:


15 + n + n + 5n + 5n - 16 = 107


by solving we find:


n = 9 runs


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j = 15 + 9 = 24 runs


d = 5n = 5*9 = 45 runs


p = 5n - 16 = 5*9 - 16 = 29 runs


Jim scored 24 runs.


Norman scored 9 runs.


Denis scored 45 runs.


Pete scored 29 runs.