Problema Solution
four brothers play in a cricket team. In their last match Jim scored 15 more runs than Norman, Dennis scored 5 times as many as Norman and sixteen more than Pete. In total they scored 107 runs. How many did each brother score?
Answer provided by our tutors
let
j = the number of runs Jim scored
n = the number of runs Norman scored
d = the number of runs Dennis scored
p = the number of runs Pete scored
In their last match Jim scored 15 more runs than Norman,
j = 15 + n
Dennis scored 5 times as many as Norman
d = 5n
and sixteen more than Pete
d = 16 + p
p = d - 16
p = 5n - 16 (since d = 5n)
In total they scored 107 runs:
j +n + d + p = 107
plug j = 15 + n, d = 5n and p = 5n - 16 into the last equation:
15 + n + n + 5n + 5n - 16 = 107
by solving we find:
n = 9 runs
click here to see the step by step solution of the equation:
j = 15 + 9 = 24 runs
d = 5n = 5*9 = 45 runs
p = 5n - 16 = 5*9 - 16 = 29 runs
Jim scored 24 runs.
Norman scored 9 runs.
Denis scored 45 runs.
Pete scored 29 runs.