Problema Solution
An artificallake is in the sape od a rectangle and has an area of 9\20 square mile. the width of the lake is 1\5 the length of the lake.What are the dimensions of the lake
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let
x = the length of the lake, x>0
(1/5)x = the width of the lake
A = 9/20 mi^2 the area of the lake
A = length*width
x*(1/5)x = 9/20
by solving we find:
x = 1.5 mi
click here to see the step by step solution of the equation:
(1/5)*1.5 = 0.3 mi
the dimensions of the lake are: 1.5 miles in length and 0.3 mi in width.