Problema Solution
how much of a 70%-alcohol solution must be mixed with 50 gallons of an 18%-alcohol solution to obtain a solution that is 60% alcohol?
Answer provided by our tutors
let
x = gallons of the 70% alcohol solution
0.70x + 0.18*50 = 0.60(x + 50)
by solving we find:
x = 210 gal
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210 gallons of 70% alcohol solution must be mixed.