Problema Solution
Wallace and Vernonville are 208 miles apart. A car leaves Wallace traveling towards Vernonville, and at the same time a car leaves Vernonville traveling toward Wallace. The car leaving Wallace averages ten mph more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the cars?
Answer provided by our tutors
let
v = the average speed of the car leaving Vernonville
v + 10 = the average speed of the car leaving Wallace
d = 280 mi the distance between Wallace and Vernonville
t = 1 hr 36 min = 1 + 36/60 hr = 1.6 hr the time of the travel
since speed = distance/time follows distance = speed*time
vt + (v + 10)t = d
1.6v + 1.6(v + 10) = 280
by solving we find:
v = 82.5 mph
click here to see the step by step solution of the equation:
v + 10 = 82.5 + 10 = 92.5 mph
the average speed of the cars are:
the average speed of the car leaving Vernonville is 82.5 mph.
the average speed of the car leaving Wallace is 92.5 mph.