Problema Solution

Two trains leave the station traveling in opposite directions. One train is 8 miles per hour faster than the other and in 2.5 hours they are 230 miles apart. Determine the average speed of each train.

Answer provided by our tutors

let


v = the average speed of the slower train


v + 8 = the average speed of the faster train


t = 2.5 hr the time of the travel


since distance = speed*time and the trains travel in opposite direction we have:


vt + (v + 8)t = 230


v*2.5 + (v + 8)*2.5 = 230


by solving we find:


v = 42 mph


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42 + 8 = 50 mph


the average speed of the slower train is 42 mph.


the average speed of the faster train is 50 mph.