Problema Solution
pam and sue left their houses at the same time and headed in opposite directions.After 4 hours,they were 440 miles apart.If pam drove 10 mph faster than sue,how fast did sue drive?
Answer provided by our tutors
let
v = the average speed of sue
v + 10 = the average speed of pam (10 mph faster than sue)
t = 4 hr the time of the travel
d = 440 mi the distance between
we will assume that pam and sue left the same location and headed in opposite directions
since speed = distance/time follows distance = speed*time
vt + (v + 10)t = d
v*4 + (v + 10)*4 = 440
by solving we find:
v = 50 mph
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sue drove with average speed of 50 mph.