Problema Solution
A rectangle has a length 5.9 feet greater than its width. It's perimeter is 51feet.
Use formula of P = 2W + 2L
Answer provided by our tutors
let
W = the width of the rectangle, W>0
L = the length of the rectangle, L>0
A rectangle has a length 5.9 feet greater than its width:
L = 5.9 + W
It's perimeter is 51 feet:
2W + 2L = 51
By solving the system of equations:
L = 5.9 + W
2W + 2L = 51
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L = 15.7 ft
W = 9.8 ft
The length is 15.7 feet and the width is 9.8 feet.