Problema Solution
three workers work 5 hours putting together beanie babies, where they are paid a fixed amount of money for each beanie baby assembled. Suppose altogether the workers earn $470 for their work. The first worker earns $200. The second worker assembles one beanie baby every 4 minutes, and the third worker receives $30 less than the second worker. Altogether, how many beanie babies do the three workers assemble?
Explain your solutions thouroughly and clearly
Answer provided by our tutors
First we will find how much the second worker earns. Then using his rate of 4 min per beanie baby we will find the fixed amount of money for each beanie baby assembled. Once we know the the fixed amount of money for each beanie baby assembled we can find the total number of beanie babies assembled by the three workers.
First worker earns: $200
Second worker earns: x
Third worker earns: x - 30
Altogether the workers earn $470 for their work:
200 + x + (x - 30) = 470
........
click here to see all the equation solution steps
........
x = $150
The second worker earns $150.
He works for 5 hours = 5*60 = 300 min.
Since he makes one beanie every 4 minutes the total number of beanie babies that he assembles is:
300/4 = 75 beanie babies
Now we will find the fixed amount of money for each beanie baby assembled by dividing the amount of money that the second worker earns by the number of beanie babies that he assembled:
150/75 = $2 per beanie baby
We know that the amount of money that the three workers earn altogether is $470 thus we divide this amount by the cost per beanie baby:
470/2 = 235 beanie babies
The three workers altogether assembled 235 beanie babies.