Problema Solution

Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer?

Answer provided by our tutors

Let 'x' represent the price of the computer


The first boy had 7/8 of the price of the computer: (7/8)x


The second boy had 5/6 of the money the first had: (5/6)(7/8)x


Together they had $696.00 more than they need to pay:


(7/8)x + (5/6)(7/8)x = 696 + x

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x = $1,152


The price for the computer was $1,152.