Problema Solution

· A rectangular Landscape element is being added to the pool complex to beautify the grounds. If the length is 8 more than twice the width and the total area is 960 square feet, find the length and width of the rectangular landscape element.

Hint: Follow the same process as problems one and two. First, draw a picture and label. Then find an algebraic expression for total area. In this case, set that expression equal to 960 square feet. Then set the equation equal to zero and don’t forget to factor out the GCF.

· Sketch out a quick drawing of the Landscape element with all dimensions labeled. This drawing will help you keep your measurements straight as you continue with the project.

Answer provided by our tutors

Let


l = the length of the rectangular landscape, l>0


w = the width of the rectangular landscape, w>0


A = 960 ft^2 the area of the rectangle landscape


The length is 8 more than twice the width:


l = 8 + 2w


The area of a rectangle is A = width*length


A = w*l


w*l = 960


plug l = 8 + 2w into the last equation:


w*(8 + 2w) = 960

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w = 20 ft


l = 8 + 2*20


l = 48 ft


The length of the rectangular landscape is: 48 ft.


The width of the rectangular landscape is: 20 ft.