Problema Solution
the height of a box holding a printer cartridge is 1 in. more than the width and the length is 9 in. more than the width. if the volume of the box is 420 in cubed, then what are the dimensions of the box
Answer provided by our tutors
let
x = the width of the box, x>0
x + 1 = the height of the box
x + 9 = the length of the box
V = 420 in^3 the volume of the box
V = width*length*height
V = x(x + 1)(x + 9)
x(x + 1)(x + 9) = 420
x(x + 1)(x + 9) - 420 = 0
by factoring the last equation we get:
........
click here to see the step by step factorization of the polynomial
........
(x - 5)(x^2 + 15x + 84) = 0
One root is x = 5.
By solving x^2 + 15x + 84 = 0 we find the other two roots:
........
click here to see all the equation solution steps
........
The roots are complex numbers which leaves us with the only possible solution x = 5 in.
x + 1 = 5 + 1 = 6 in
x + 9 = 5 + 9 = 14 in
The dimensions of the box are: the width is 5 inches, the length is 14 inches and the height is 6 inches.