Problema Solution
two cars leave a city and head in the same direction. after 12 hours the faster car is 4 miles ahead of the slower car. the slower car has traveled 98 miles. find the speed of the two cars.
Answer provided by our tutors
Let
v1 = the speed of the faster car
v2 = the speed of the slower car
After 12 hours the faster car is 4 miles ahead of the slower car:
12(v1 - v2) = 4
The slower car has traveled 98 miles:
12*v2 = 98
We have the following system of equations:
12(v1 - v2) = 4
12*v2 = 98
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v1 = 8.6 mph
v2 = 8.17 mph
The speed of the faster car is 8.6 mph.
The speed of the slower car is 8.17 mph.