Problema Solution

the difference between ages of two cousins is 10 years. 15 years ago ,if the elder one was twice as old as the younger one,find their present ages

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Let


x = the present age of the elder cousin, x>0


y = the present age of the younger cousin, y>0


x>y


the difference between ages of two cousins is 10 years:


x - y = 10


15 years ago the elder one was twice as old as the younger one:


x - 15 = 2(y - 15)


We have the following system of equations:


x - y = 10


x - 15 = 2(y - 15)

........


click here to see all the system of equations solution steps


........

x = 35 years


y = 25 years


The present age of the elder cousin is 35 years.


The present age of the younger cousin is 25 years.