Problema Solution
If a pro basketball player has a verticle leap of about 20 inches, what is his hang time? Use hang-time function V= 48T^2
The hangtime is___________ seconds
Answer provided by our tutors
The problem gives you:
v=48t^2
where
v is "vertical leap" (in inches)
t is time (in seconds)
Plug in the given "vertical leap" of 20 inches and solve for t:
v=48t^2
20=48t^2
20/48 = t^2
0.645 seconds = t (hang time)