Problema Solution
The height h, in feet, of a golf ball t seconds after it has been hit is given by the equation h = −16t2 + 62t. How many seconds after the ball is hit will the height of the ball be 42 feet? Round answers to nearest hundredth.
Answer provided by our tutors
h(t) = −16t^2 + 62t
we need to find t, t>0 such that h(t) = 42 ft that is:
−16t^2 + 62t = 42
........
........
t1 = 0.875 s
t2 = 3 s
The height of the ball will be 42 ft, first after 0.875 seconds, and then again 3 seconds after the hit.