Problema Solution
the perimeter of a rectangle is 300 yards. whatare the demintions of the rectanglle if the length is 30 yards more than the width?
Answer provided by our tutors
Let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
The length is 30 yards more than the width:
l = 30 + w
The perimeter of a rectangle is 300 yards:
2(l + w) = 300
By solving the system of equations:
l = 30 + w
2(l + w) = 300
........
........
l = 90 yd
w = 60 yd
The dimensions of the rectangle are: the length is 90 yards and the width is 60 yards.