Problema Solution

One integer is 4 less than another. The sum of their squares is 58. Find the integers.

Answer provided by our tutors

Let x and y represent the integers and x>y


One integer is 4 less than another:


y = x - 4


The sum of their squares is 58:


x^2 + y^2 = 58


Plug y = x - 4 into the last equation:


x^2 + (x - 4)^2 = 58

........


click here to see all the equation solution steps


........

x1 = 7


x2 = -3


For x = 7 we find y = 7 - 4 = 3, the two integers are 7 and 3.


For x = -3 we find y = -3 - 4 = -7, the two integers are -3 and -7.