Problema Solution
One integer is 4 less than another. The sum of their squares is 58. Find the integers.
Answer provided by our tutors
Let x and y represent the integers and x>y
One integer is 4 less than another:
y = x - 4
The sum of their squares is 58:
x^2 + y^2 = 58
Plug y = x - 4 into the last equation:
x^2 + (x - 4)^2 = 58
........
........
x1 = 7
x2 = -3
For x = 7 we find y = 7 - 4 = 3, the two integers are 7 and 3.
For x = -3 we find y = -3 - 4 = -7, the two integers are -3 and -7.