Problema Solution
A ball is thrown vertically upward from the ground. Its distance in feet from the ground is s=-16t+128t. After how many seconds will the ball be 192 feet from the ground?
Answer provided by our tutors
s=-16t^2+128t, where t is the time in seconds, t>0
We need to find t such that s = 192 ft that is:
-16t^2+128t = 192
........
........
t1 = 2 s
t2 = 6 s
The ball will be 192 feet from the ground two times: after 2 seconds and after 6 seconds from the throw.