Every odd integer can be written as 2k + 1, where k is integer

The 3 consecutive odd positive integers can be written as:

2k - 1, 2k + 1, 2k + 3, where k is integer, 2k-1>0, k>1/2

5 times the sum of all three is 66 more than the product of the first and second integers:

5(2k - 1 + 2k + 1 + 2k + 3) = 66 + (2k - 1)(2k + 1)

........

........

k = 5

2*5 - 1 = 9

2*5 + 1 = 11

2*5 + 3 = 13

The three consecutive odd positive integers are 9, 11 and 13.