Problema Solution
A school playground is a 25 m by 40 m rectangle. The school increases the width to 40 m and increases the length so that the original rectangle and the new one are similar. By how much does the perimeter of the playground increase?
Answer provided by our tutors
Let x represent the increased length, x>0
24 : 40 = 40 : x
........
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x = 64 m
The perimeter of the original school playground is: 2*(24 + 40)
The perimeter of the new school playground is: 2*(40 + 64)
The perimeter will increase by: 2*(40 + 64) - 2*(24 + 40) = 80 m.