Problema Solution
A small rock sits on the edge of a tall building. A strong wind blows the rock off the edge. The distance, in feet, between the rock and the ground tseconds after the rock leaves the edge is given by d=−16t2−5t+500.
If the answer is not an integer, enter it as a decimal. Round to the nearest hundredth, if needed.
How many seconds after the rock leaves the edge is it 449feet from the ground?
seconds
How many seconds after the rock leaves the edge does it hit the ground?
seconds
Answer provided by our tutors
How many seconds after the rock leaves the edge is it 449feet from the ground?
d = 449 ft
−16t^2−5t+500 = 449
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t = 1.64 seconds
How many seconds after the rock leaves the edge does it hit the ground?
d = 0
−16t^2−5t+500 = 0
........
........
t = 5.44 seconds.