Problema Solution
A can of soda at 83 F is placed in a refrigerator that maintains a constant temperature of 35 F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by T(t) = 35 + 48e^ -0.058t
Find the temperature of the soda 15 minutes after it is placed in the refrigerator
Answer provided by our tutors
T(t) = 35 + 48e^ -0.058t
t = 15 min
T(15) = 35 + 46*e^(-0.058*15)
........
........
T(15) = 54.27 F
The temperature after 15 minutes will be 54.27 F.