Problema Solution
Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to Player A had 14 fewer runs batted in for the 2006 regular season. Together, these two players brought home 232 runs during the 2006 regular season. How many runs batted in did Player A and Player B account for?
Answer provided by our tutors
Let
a = the number of runs batted in that the Player A had
b = the number of runs batted in that the Player B had
Player B, who came in second to Player A had 14 fewer runs batted in for the 2006 regular season:
b = a - 14
Together, these two players brought home 232 runs during the 2006 regular season.
a + b = 232
We have the following system of equations:
b = a - 14
a + b = 232
........
........
a = 123 runs
b = 109 runs
Player A had 123 runs batted in.
Player B had 109 runs batted in.