Problema Solution
find the length of a rectanglular lot with a perimeter of 108 meters if the length is 8 meters more than the width.
Answer provided by our tutors
Let
w = the width, w>0
l = the length, l>0
P = 108 m the perimeter
The length is 8 meters more than the width:
l = 8 + w
The perimeter P = 2(l + w)
2(l + w) = 108
We have the following system of equations:
l = 8 + w
2(l + w) = 108
........
........
l = 31 m
w = 23 m
The length is 31 meters.