Problema Solution
five years ago, megan's age was 5 years less than twice tony's age. In three years, one third of tony's age will be 12 years less than megan's age. how old are they now?
Answer provided by our tutors
Let
m = Megan's age now
t = Tony's age now
Five years ago, megan's age was 5 years less than twice Tony's age:
m - 5 = 2(t - 5) - 5
In three years, one third of tony's age will be 12 years less than Megan's age:
(1/3)(t + 3) = (m + 3) - 12
We have the following system of equations:
m - 5 = 2(t - 5) - 5
(1/3)(t + 3) = (m + 3) - 12
........
........
t = 12 years
m = 14 years
Megan is 14 years old now.
Tony is 12 years old now.