Problema Solution
The length of a rectangle is 6 inches longer than its width. What are the possible widths if the area of the rectangle is at least 667 square inches?
Answer provided by our tutors
Let
x = the width of the rectangle, x>0
x + 6 = the length of the rectangle
The area of the rectangle is A = width*length or in our case:
A = x(x + 6)
The area of the rectangle is at least 667 square inches:
A >= 667
x(x + 6) >= 667
........
........
x >= 23 in
The possible width is at least 23 inches.