Problema Solution
area of rectangle is 66 yd length is 1 yd more than twice its width. what are the dimensions
Answer provided by our tutors
Let
x = the width, x>0
2x + 1 = the length
A = 66 yd^2 the area of the rectangle
A = width*length
A = x(2x + 1)
x(2x + 1) = 66
........
........
x = 5.5 yd
2x + 1 = 2*5.5 + 1 = 12 yd
The width is 5.5 yd and the length is 12 yd.