Problema Solution
In his pocket, robert has $1.65 in quarter, dimes, and nickels. He has 11 coins in all, with twice as many nickels as dimes. How many of each coin does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
Let
n = the number of nickels, n>0, n is integer
d = the number of dimes, d>0, d is integer
q = the number of quarters, q>0, q is integer
Robert has $1.65 = 165 cents in quarter, dimes, and nickels:
25q + 10d + 5n = 165
He has 11 coins in all:
q + d + n = 11
with twice as many nickels as dimes:
n = 2d
We have the following system of equations:
25q + 10d + 5n = 165
q + d + n = 11
n = 2d
........
........
q = 5 quarters
d = 2 dimes
n = 4 nickles
Robert has 4 nickles, 2 dimes and 5 quarters.