Problema Solution
If a liter of chemical X is 95% pure, how many liters of water must be added to make a 50% solution?
Answer provided by our tutors
Let 'x' represent the liters of water (0% of solution)
0.95*1 + 0*x = 0.50(1 + x)
........
........
x = 0.9 L
0.9 liters of water must be added.