If a + b = 5 and ab = 6 , then find the value of 4(a2 - b2) – a3 + b3 , if a > b .

(a-b)^2=(a+b)^2-4ab.

=5^2-4*6

=1.

a-b=sqrt(1) =1.

a+b=5.

a-b=1. By adding

2a=6

a=3, b=2.

4(a^2-b^2)=4(3^2-2^2).

=20.

a^3+b^3=3^3+2^3.

=27+8.

=35.