he sum of three numbers is negative 48.The first number is twelve more than the second number and the third number is 20 less than twice the second number. Find the three numbers.

Let x, y, z b ethe three numbers.

x+y+z=-48.

x=y+12.

z=2y-20.

y+12+y+2y-20=-48.

4y-8=-48.

4y=-48+8=-40.

y=-40/4=-10.

x=y+12=-10+12=2.

z=2y-20=2*-10-20

-50

The three numbers are 2,-10,-50.