Problema Solution
find two consecutive odd positive intigers whose squares differ by 6.
Answer provided by our tutors
let the first integer is X
so, next consecutive integer will be = X+2
from ques, we have (X+2)^2- X^2 = 6
i.e, x^2+4+2x=6
or, x^2+2x-2 =0
or,(x-1)*(x-1)=0 -- breaking this into factors
i.e, x=1, and x+2 =3.
therefore (1,3) are two such consecutive odd nos.