Problema Solution
Kenneth had $90 more than Jane. When Kenneth gave 60% of his money to Jane, Jane had $30 more than Kenneth. How much money did Jane have at first?
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K=9+J.
J=30+0.4K.
J=30+0.4(9+J).
J=30+3.6+0.4J
J-0.4J=33.6
J=33.6/0.6
=$56.
Jnae have $56 first.
0.4J=35.4
J=35.4/0.4
J=$88.50.