Problema Solution
The sum of the squares of two consecutive even integers is 724. Find the integers.
Answer provided by our tutors
Let the first be x. Then the other is x+2.
Have x^2 + (x+2)^2 = 724
So x^2 + (x^2 + 4x + 4) = 724
2x^2 + 4x - 720 = 0
x^2 + 2x - 360 = 0
(x - 18)(x + 20) = 0
So x = 18 since x > 0.
One more line: the two integers are 18 and 20.