Problema Solution
A triangular space between three streets has measurement of 66 meters, 130 meters and 112 meters.How much is needed to go around the space? How much sod will be needed to cover space?
Answer provided by our tutors
The perimeter if = 66+112+130 = 308 meters (length to go around)
The area A= sqrt(s(s-a)(s-b)(s-c)) (heron's formula) where s = (a+b+c)/2
When a=66, b=112 and c=130 -> s= (308/2) = 154
Therefore Area A = 3696 meter^2 (this much of sod area is needed)