Problema Solution
Suppose that Javier has a handful of coins, consisting of pennies, nickels, and dimes, worth $2.63. The number of nickels is 1 less than twice the number of pennies, and the number of dimes is 3 more than the number of nickels. How many coins of each kind does he have?
Answer provided by our tutors
Let x be the number of pennies.
"The number of nickels is 1 less than twice the number of pennies"
means the number of nickels is 2x - 1.
"the number of dimes is 3 more than the number of nickels"
means the number of dimes is 2x - 1 + 3 = 2x + 2.
They worth 2.63 so
x + 5(2x-1) + 10(2x+2) = 263
x + 10x-5 + 20x+20 = 263
31x + 15 = 263
31x = 248
x = 8
ANS: 8