Problema Solution
A chemist has two acid solution. One is 60% acid solution and the other is 30% acid solution. How many liters of each should she mix so that she obtains 10 liters of 51% of acid solution?
Answer provided by our tutors
We assume the two acid solution is x and y, so the sum of two solutions is (x+y)
The equation si
x + y = 10
60%*x + 30%*y = 51%*10
We solve it
x = 7
y = 3
So
60% acid solution: 7 litters
30% acid solution: 3 litters