Problema Solution
Jay is twice as old as Larry. in 3 years the sum of their ages will be 54. how old are they now?
Answer provided by our tutors
J = 2L
(J+3) + (L+3) = 54
Put J=2L in second equation:
(2L+3) + (L+3) = 54
3L+6= 54
3L= 48
L= 16 years
so, J=2L means J = 16*2 = 32 years
Age of Jay = 32 years,
age of Larry = 16 years
(1)
---
(a) 6
(b) 6x+1
(2)
---
9x+10
(3)
---
(1/22)x + 11/2
(7)
---
(a) 8a - 3a^2
(b) 4x
(c) -3x + 18
(8)
---
8/(t+3)^2
PARTICLE QUESTIONS
(a) (0,1) (4,6)
(b) (2,3)
(c) (1,2) (3,4)