Problema Solution
A BOWLING BALL IS RELEASED WITH A FINAL VELOCITY OF 7m/s AFTER IT ACCELERATES UNIFORMLY FOR 0.5 seconds STARTING FROM REST. THE MASS OF THE BALL IS 8KG. HOW MUCH FORCE IS EXERTED BY THE BOWLER?
Answer provided by our tutors
The accelarate rate: a = 7m/s/0.5s = 14 m/s^2
We assume the force exerted by the bowler is F
F = m*a = 8*14 = 112 N
So the force exerted by the bowler is 112 N