Problema Solution
A rectangular painting measures 13 inches by 17 inches and contains a frame of uniform width around the four edges. The perimeter of the rectangle formed by the painting and its frame is 92 inches. Determine the width of the frame.
Answer provided by our tutors
width= 13+2x
length= 17+2x
so, perimeter= 2(13+2x+17+2x)
92= 2(4x+30)
46= 4x+30
4x=16
x=4
so, 4 inches is the width of the frame.