Problema Solution
passing through (-4,3 times the square root of 3/2) and (8 times the square root of 5/3,-2).solve for the equation of an ellipse.
Answer provided by our tutors
We assume the equation of an ellipse is x^2/(a^2) + y^2/(b^2) = 1
Because it passes through (-4,3 square root of 3/2) and (8 square root of 5/3,-2),so
(-4)^2/(a^2) + [3sqrt(3/2)]^2/(b^2) = 1
[8sqrt(5/3)]^2/(a^2) + (-2)^2/(b^2) = 1
We solve it
a^2 = 258/17
b^2 = 2752/19
So
the equation of an ellipse is 19x^2/2752 + 17y^2/258 =1