Problema Solution
how many gallons of 20% antifreeze solution should be mixed with 16 gallons of 10% antifreeze solution to obtain a mixture that is 16% antifreeze solution?
Answer provided by our tutors
0.16 = 0.10(16) + 0.20x/(x + 16)
0.16(x +16) = 1.6 + 0.20x
0.16x + 2.56 = 1.6 + 0.20x
0.96 = 0.04 x
x = 24 gallons