Problema Solution
A man has a number of coins which are dimes and quarters. The value of the coins is $2.95. If the dimes were quaters and the quarters were dimes, the value of the coins would be $3.70. How many dimes and how many quarters does he have?
Answer provided by our tutors
suppose dimes = x
and quarters = y
10x +25y = 295
25x + 10y = 370
Solving we get
x = 12, y =7
dimes = 12
quarters = 7